Test diagnostyczny z algebry

(a) $(-4{)}^4=$

(b) $-4^4=$

(c) $\frac{3^{25}}{3^{22}}=$

(d) ${\left(\frac{3}{4}\right)}^{-2}=$

(a) $\sqrt{300}–\sqrt{27}=$

(b) $(5x^3{y}^2)(2x{y}^4{)}^2=$

(c) ${\left(\frac{2a^2{b}^5}{a^{1/2}{b}^2}\right)}^{-2/3}=$

(a) $3x–2(4x–5)+x=$

(b) $2(x+4)–3(2x–5)=$

(c) $(x–\sqrt{5})(x+\sqrt{5})=$

(d) $(2x–3{)}^2=$

(a) $9x^2–16=$

(b) $x^4+8x=$

(c) $x^3–2x^2–6x+12=$

(d) $x{y}^3–9xy=$

(a) $\frac{2x^2–x–1}{x^2–25}\cdot \frac{x+5}{2x+1}=$

(b) $\frac{x^2}{x^2–4}–\frac{x+1}{x+2}=$

(a) $\frac{\sqrt{10}}{\sqrt{3}–2}=$

(b) $\frac{\sqrt{a+4}–2}{a}=$

(a) $4x^2+4x+2=$

(b) $x^2–6x+12=$

(a) $5x–7=3x+9$, $x=$

(b) $\frac{2x–1}{3}=5$, $x=$

(c) $x^2–6x+8=0$, $x\in$

(d) $3|x–2|=8$, $x\in$

(a) $x(x–3)(x+5)⩾0$, $x\in$

(b) $x^2<2x+3$, $x\in$

(c) $\frac{3x–1}{x+1}>2$, $x\in$

$x=$

$y=$

$x=$

$y=$

$z=$

$x=$

$y=$